Programmer - Taking user input with pointers

Programmer Question

I'm trying to get better at using pointers, and not using array notation. So I have a function to read user input and return a pointer to that array. I can do it like this and it seems to work ok:

float *GetValues(float *p, size_t n) 
{   

    float input;
    int i = 0;

    if ((newPtr = (float *)malloc(n * sizeof(float))) == NULL) {
        cout << "Not enough memory\n";
        exit(EXIT_FAILURE);
    }
    cout << "Enter " << n << " float values separated by whitespace: \n";

    while (scanf("%f", &input) == 1) {
        p[i] = input;
        i++;
        cout << *p;
    }
    return p;
}

But then if I do this:

float *GetValues(float *p, size_t n) 
{   
    float *newPtr;
    float input;

    if ((newPtr = (float *)malloc(n * sizeof(float))) == NULL) {
        cout << "Not enough memory\n";
        exit(EXIT_FAILURE);
    }
    cout << "Enter " << n << " float values separated by whitespace: \n";

    while (scanf("%f", &input) == 1) {
            *newPtr++ = input;
    }
    return newPtr;
}

I get just 0s entered into p. Why is that?

Also, do I have to allocate memory here for an array of size n? I first tried it with the method above using pointers and not allocating memory but just set p = to input and I was getting garbage values. Thanks!

Edited: Sorry, I allocated a new ptr and was returning the wrong one like you said. I was just trying to input the numbers into my pointer and display it back on the screen to myself and wasn't paying attention to the return type and I was getting an output of 0 when I would cout << *newPtr.